(4a-3)^2+11a=(a+2)(a-2)+33

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Solution for (4a-3)^2+11a=(a+2)(a-2)+33 equation:



(4a-3)^2+11a=(a+2)(a-2)+33
We move all terms to the left:
(4a-3)^2+11a-((a+2)(a-2)+33)=0
We add all the numbers together, and all the variables
11a+(4a-3)^2-((a+2)(a-2)+33)=0
We use the square of the difference formula
a^2+11a+(4a-3)^2+4=0
We move all terms containing a to the left, all other terms to the right
a^2+11a+(4a-3)^2=-4

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